bluelouse950Lv1
13 Nov 2021
Problem 27b
Page 280
Section 4.3: Derivatives and Shapes of Curves
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
13 Nov 2021
Given information
Given:-
critical numbers
Step-by-step explanation
Step 1.
we have found the first derivative of the function in part one.
Now, To find the local maximum and minimum values of the function we determine the intervals around the critical numbers.
if we put the value of in the derivative we found the intervals
if we put the value of in the derivative. so there is not any relative extremum at this point.
now choose one point from each of them
so the function has a local minimum value at,
now put the value of in the given function