Textbook ExpertVerified Tutor
18 Nov 2021
Given information
It is given that the focal length of the mirror 
cm
The object distance is 
cm
Equation 23-2 states the mirror formula 
Step-by-step explanation
Step 1.
Here the object distance is positive because it is located in front of the mirror, towards the left of the mirror. The focal length is given a negative sign signifies that the distance is measured towards the right side of the mirror, behind the mirror.
On substituting the values in the mirror formula gives
cm
So the image is formed towards the right of the mirror that is behind the mirror
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5
- Problem 6a
- Problem 6b
- Problem 7
- Problem 8
- Problem 9
- Problem 10a
- Problem 10b
- Problem 10c
- Problem 11a
- Problem 11b
- Problem 11c
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20a
- Problem 20b
- Problem 20c
- Problem 20d
- Problem 21a
- Problem 21b
- Problem 21c
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26a
- Problem 26b
- Problem 26c
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32a
- Problem 32b
- Problem 32c
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39a
- Problem 39b
- Problem 39c
- Problem 40a
- Problem 40b
- Problem 41a
- Problem 41b
- Problem 42a
- Problem 42b
- Problem 43a
- Problem 43b
- Problem 44
- Problem 45a
- Problem 45b
- Problem 45c
- Problem 45d
- Problem 46
- Problem 47a
- Problem 47b
- Problem 48a
- Problem 48b
- Problem 48c
- Problem 49
- Problem 50a
- Problem 50b
- Problem 51a
- Problem 51b
- Problem 52
- Problem 53
- Problem 54a
- Problem 54b
- Problem 55
- Problem 56
- Problem 57
- Problem 58
- Problem 59
- Problem 60
- Problem 61a
- Problem 61b
- Problem 61c
- Problem 62a
- Problem 62b
- Problem 63
- Problem 64
- Problem 65
- Problem 66
- Problem 67
- Problem 68