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24 Nov 2021
Given information
Given values:
The oscillator's fundamental frequency is Hz.
The mass per unit length of the string is .
The length of the string is m.
Step-by-step explanation
Step 1.
The string must vibrate in a standing wave pattern to have a certain number of loops.
The frequency of the standing waves will be the same as the oscillator, which is Hz.
That frequency is also expressed in
.
The speed of waves on the string is given by
The weight of the masses dangling from the string's end will equal the strain in the string,
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