6 Jan 2022
Problem 34
Page 268
Section 4.2: Maximum and Minimum Values
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
6 Jan 2022
Given information
Given that 
Step-by-step explanation
Step 1.
is differentiable at all points in the domain, because its a sum of two differentiable functions. Hence, the critical numbers are the solutions of the equation 
Differentiate
The critical numbers are the solutions of 
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1
- Problem 2a
- Problem 2b
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11a
- Problem 11c
- Problem 11c
- Problem 12a
- Problem 12b
- Problem 13a
- Problem 13b
- Problem 14a
- Problem 14b
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43
- Problem 44
- Problem 45
- Problem 46
- Problem 47
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57a
- Problem 57b
- Problem 58a
- Problem 58b
- Problem 59a
- Problem 59b
- Problem 60a
- Problem 60b
- Problem 61
- Problem 62
- Problem 63
- Problem 64a
- Problem 64b
- Problem 65a
- Problem 65b
- Problem 65c
- Problem 66a
- Problem 66b