Problem 8
Page 268
Section 4.2: Maximum and Minimum Values
Chapter 4: Applications of Differentiation
Given information
Function is continuous in the given domain 
but no information about it's differentiability is given so, for the given problem simple function that is continuous within the domain will be a straight line or linearly variable function. Also the function has absolute minimum at 
, absolute maximum at 
, local maximum and local minimum at 
and 
respectively.
Step-by-step explanation
We will start at point of absolute minimum, assume value of function at this point be 
, function has local maximum at , therefore assume function value at this point to be greater than , let's say 
, again function has local minimum at , so assume value of function to be less than , let's say 
, and finally function has absolute maximum at , so assume value of function at this point greater than value of function at local maximum, let's say 4.
Single Variable Calculus: Early Transcendentals
Solutions
Chapter
Section
- Problem 1
- Problem 2a
- Problem 2b
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11a
- Problem 11c
- Problem 11c
- Problem 12a
- Problem 12b
- Problem 13a
- Problem 13b
- Problem 14a
- Problem 14b
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43
- Problem 44
- Problem 45
- Problem 46
- Problem 47
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57a
- Problem 57b
- Problem 58a
- Problem 58b
- Problem 59a
- Problem 59b
- Problem 60a
- Problem 60b
- Problem 61
- Problem 62
- Problem 63
- Problem 64a
- Problem 64b
- Problem 65a
- Problem 65b
- Problem 65c
- Problem 66a
- Problem 66b