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PHIL 1100 : Wisdom

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tancrab558
13 Dec 2011
School
York University
Department
Philosophy
Course
PHIL 1100
Professor
Anita Lam

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Document Summary

Says the meaning of life is like a formula . That the meaning and purpose of life is to achieve this reward which is intrinsically valuable (and also meaningful) nozick, 226. Giving sisyphus a purpose to finish the temple. American man looks for the meaning of life. Quote so heavily is it laden with our emotion and aspiration that we camouflage our vulnerability with jokes about seeking for the meaning or purpose of life: a person travels for many days to the. Himalayas to seek the word of an indian holy man meditating a isolated (nozick, 224). Answer: life is like a fountain searched for the meaning of life found that is a fountain

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Related Questions

In this problem, let us consider that the two moving objects undergo collision such that after the collision, the objects stick together and travel off as a single unit. This is totally inelastic form of collision.

You are probably familiar that "momentum is conserved" in an inelastic collision. Solve the questions given below to clarify the meaning and implications of "momentum is conserved."

1)What physical quantities are conserved in this type of inelastic collision?
a) the magnitude of the momentum only
b) the net momentum (considered as a vector) only
c) the momentum of each object considered individually

2) Two cars of equal mass collide inelastically and stick together after the collision. Before the collision, their speeds are V1 and V2 . What is the speed of the two-car system after the collision?
a) V1+V2
b) V1-V2
c) V2-V1
d)(V1V2)^(1/2)
e) (1/2)(V1+V2)
f)(V1+V2)^(1/2)
g)The answer depends on the directions in which the cars were moving before the collision.

3) Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are P1 and P2 . After the collision, what is the magnitude of their combined momentum?

a) P1+P2
b) P1-P2
c) P2-P1
d)(P1P2)^(1/2)
e) (1/2)(P1+P2)
f)(P1+P2)^(1/2)
g)The answer depends on the directions in which the cars were moving before the collision.

4) Two cars collide inelastically and stick together after the collision. Before the collision, their momenta are p1 and p2. After the collision, their combined momentum is vector p. Of what can one be certain?

a) Vector P= p1+p2
b) Vector P= p1-p2
c) Vector P= p2-p1

 

In this problem we will consider a collision of two moving objects such that after the collision, the objects stick together and travel off as a single unit. The collision is therefore completely inelastic.

You have probably learned that "momentum is conserved" in an inelastic collision. But how does this fact help you to solve collision problems? The following questions should help you to clarify the meaning and implications of the statement "momentum is conserved."

1)What physical quantities are conserved in this collision?
a) the magnitude of the momentum only
b) the net momentum (considered as a vector) only
c) the momentum of each object considered individually

2) Two cars of equal mass collide inelastically and stick together after the collision. Before the collision, their speeds are V1 and V2 . What is the speed of the two-car system after the collision?
 g)The answer depends on the directions in which the cars were moving before the collision.

3) Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are P1 and P2. After the collision, what is the magnitude of their combined momentum?

a) P1+P2
b) P1-P2
c) P2-P1
d)(P1P2)^(1/2)
e) (1/2)(P1+P2)
f)(P1+P2)^(1/2)
g)The answer depends on the directions in which the cars were moving before the collision.

4) Two cars collide inelastically and stick together after the collision. Before the collision, their momenta are p1 and p2. After the collision, their combined momentum is vector p. Of what can one be certain?

a) Vector P= p1+p2
b) Vector P= p1-p2
c) Vector P= p2-p1

Part 2 is here :

http://www.cramster.com/answers-nov-10/physics/rotating-pendulum-part-2-rotating-pendulum-part-ii-note-part-httpww_1015121.aspx

This is the same rotating pendulum of the previous two problems.Now it is time to analyze the different types of motion andequilibrium (according to the initial conditions).
Note: The “effective potential” method is a powerful tool to analyzeand solve problems where the Hamiltonian is conserved. A similartechnique is used for central potentials, including the Keplerproblem of celestial mechanics (two-body gravitationalproblem)—will see that later.
(a) Let us call Eeff ≡ H the “effective energy.” To make it look likea real energy, define Eeff = T2 + Veff , where Veff should include therelevant non-quadratic piece of kinetic energy (which effectivelybehaves, with an appropriate sign, as a potential energycontribution). In short, the effective potential is defined so thatthe effective kinetic energy left in the Hamiltonian is justquadratic.
Your task: Find the corresponding effective potential Veff (θ), i.e.,write it down explicitly as a function of θ.
Hint: Using the resolution T = T0 + T1 + T2 , it should follow thatVeff = V − T0 (using
Euler’s theorem for homogeneous functions).
(b) Analyze all possible shapes of the graph of the effectivepotential Veff (θ) (versus θ). For this purpose, simply use calculusand the techniques for energy graphs that we studied withone-dimensional systems. Specifically, you should plot Veff (θ) andfind the extrema.
Hint: There should be two different regimes (or two “families” ofshapes).
(c) At what rotation rate ωc does the stationary point at θ = 0become unstable?
(d) For ω > ωc , what is the stable equilibrium value ofθ?
Explain the physical meaning of this stable “dynamic equilibrium”value. Also explain in simple terms why θ = 0 is a stable “dynamicequilibrium” position for ω < ωc .
(e) What is the frequency Ω of small oscillations about the“dynamic equilibrium” points (for each of the two regimesdiscovered above)? Compute this frequency in two differentways:
(i) using the effective potential; and (ii) linearizing the equationof motion.