MATH 151 Midterm: MATH 151 TAMU Y2010 2010c Exam 1b Solutions
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Solutions-form b: c: a force ~f = 2~i + 6~j moves an object from the point p (1, 3) to the point q(3, 7). W = ~f ~d = h2, 6i h2, 4i = 28 foot pounds. length 2, compute ba bc. | bc| = 2, and since the triangle is equilateral, Hence ba bc = | ba|| bc| cos : d: if abc is an equilateral triangle with sides of (2)(2) cos 60 = 2, a: the parametric equations x = 3 + sin t, y = The direction vector is h 5, 6i = h 6, 5i. Thus the slope of the line with direction vector h 6, 5i is. 6: b: find the vector ~a that has magnitude |~a| = 12 and makes an angle of 300 with the positive x-axis. Since 300 = 360 60 , our reference angle is 60 in quadrant iv.
