CHEM 115 Midterm: Exam 4 Study Guide

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Chapter 5 (5. 7), chapter 6 (no math problems from 6. 4), chapter 7, chapter 8 (8. 1-8. 4) [(cid:888)(cid:4666) (cid:885)(cid:891)(cid:885). (cid:887) (cid:1863)(cid:4667)+(cid:885)(cid:4666) (cid:884)(cid:890)(cid:887). (cid:890)(cid:1863)(cid:4667)] [(cid:4666)(cid:886)(cid:891). (cid:882) (cid:1863)(cid:4667)+ (cid:2869)(cid:2870)(cid:2870)(cid:4666)(cid:882) (cid:1863)(cid:4667): (cid:2874)(cid:2874)(cid:4666)(cid:1864)(cid:4667):(cid:4672) (cid:2871)(cid:2870)(cid:2874)(cid:2875) (cid:3038)(cid:3040)(cid:3042)(cid:3039) (cid:4673)(cid:4672)(cid:2869) (cid:3040)(cid:3042)(cid:3039, (cid:3033)=[ (cid:3033)(cid:4666)(cid:1873)(cid:4667)+ (cid:3033)(cid:4666)(cid:2870)(cid:4667)] [ (cid:3033)(cid:4666)(cid:1873)(cid:4667)+ (cid:3033)(cid:4666)(cid:2870)(cid:4667)] (cid:2875)(cid:2876). (cid:2869) (cid:3034)(cid:4673)= (cid:2872)(cid:2869). (cid:2876) (cid:3038)(cid:3034) 129. 7 kj = [0 + (-285. 8)] [(cuo) + (0): cuo = -156. 1 kj/mol, calculate the standard enthalpy of formation of cuo(s), cuo(s) + h2(g) cu(s) + h2o(l) h = -129. 7 kj. = =((cid:885). (cid:882)(cid:882) (cid:883)(cid:882)(cid:2876)(cid:1865) (cid:887)(cid:890)(cid:891) (cid:1866)(cid:1865) )((cid:883) (cid:1866)(cid:1865)(cid:883)(cid:882) (cid:2877)(cid:1865)) Calculate the energy of one photon of yellow light that has a wavelength of 589 nm. 6. 3 v = c/ (cid:540) v = (3. 00 x 108 m/s)(1 nm/ 10-9 m) = 5. 09 x 1014 s-1. Possible values of ml number of orbitals in subshell. 3p6, 4s2, 3d9: occurs because 4s and 3d orbitals very close, mo, pd, ag also show these anomalies.

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