CHEM101 Lecture 7: January 21: Quantum Number review, d orbital shapes and energies, fourth quantum number, and multielecton atoms

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24 Jan 2019
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They are the solution to the schr dinger equation and they tell us where electrons can be based on probability. The quantum numbers all together create an orbital. n = integers excluding 0, so n=1,2,3,4 . =0,1,2,3,4 m =0 m =-1,0,+1 m = -2,-1,0,+1,+2 m = -3,-2,-1,0, +1,+2,+3 m = +4,-3,-2,-1,0,+1,+2,+3,+4. S orbitals have an =0 and they are a spherical shape. 1s has no nodes, 2s have 1 node, and 3s has 2 nodes. Nodes are a section in the orbital where there is a 0% probability of finding electrons. The amount of nodes present in a certain orbital is equivalent to the value which is n-1. Orbital shapes and energies d orbitals have values of 2 or 3. m values would then be equivalent to -2,- 1,0,+1,+2. m is also an important quantum number which describes the spin of an electron. There are 5 d orbitals, 4 of them look very similar but have different locations.

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