BIOL 234 Lecture 11: Pedigree Notes

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ceruleanswan43

15 Dec 2018

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When calculating probabilities, you have to multiply together all the events that would have to happen in order to have a specific outcome. Calculating the probability that ? (iii-1) would be affected requires that you multiply. Iii-1 would have to get a disease allele from both parents. The chance that the father donates a disease allele is 1 (because he has to be homozygous for the disease allele). In order for the iii-1 to get a disease allele from the mother, that mother ii-3 has to be a carrier and pass on the disease allele. Her parents i-1 and i-2 have to both be carriers because they have an affected daughter ii-2. The chance then that ii-3 is a carrier is 2/3 just like the slide i showed you at the top. When there is more than one way that you could get a particular outcome, you add together all those different ways for your probability calculation.

Related Questions

5. If 1/1000 individuals with your genetic background are carriers for a certain autosomal, recessive disease allele, what is the chance that both you and your spouse will be carriers?

6. (Related to 5) What is the chance that you will both be carriers and have an affected child?

7. (Related to 5 and 6) If you are a carrier for this disease allele and your spouseâs status is unknown, what is you chance of having a child with the disease?

apricotwhale125

Two parents who are each known to be carriers of an autosomalrecessive allele have four children. None of the children has therecessive condition.

What is the probability that two or more of the children are thecarriers of the recessive allele?

(To calculate this type of probability, you must consider allpossible birth orders of carriers. For example, if a question askedwhat is the probability the one of two children is a carrier, thereare two possible orders: 1) first child is a carrier, second childis not a carrier 2) first child is not a carrier, second child is acarrier. Calculate the probability of each possible occurance andadd the probabilities together to get the overall chance that onechild is a carrier. )

beigecoyote614

1. Neurofibromatosis is inherited as a dominant gene. If a young child is the first in her family to be diagnosed (the proband), and the disease has a full penetrance in the corresponding population, which of the following is correct?

A. The mother is the carrier of the allele

B. The mutation has occured in gametogenesis of one of the parents

C. The condition will skip some generations in the family

The child will certainly have normal siblings with the abnormal genotype.

Both parents cannot be free from the disorder- one of them will certainly display the symptoms later in life.

F. Either infidelity is involved, or the child is not the biological offspring of her parents.

2. A man who suffers from a Y-linked disease marries a normal woman who has a red-green color blind (XLR) maternal grandfather. What is the chance that the couple will have a child affected with both conditions?

	A.	Zero
	B.	25%
	C.	50%
	D.	12.5%
	E.	100%

BIOL 234 Lecture 11: Pedigree Notes

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