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Statistics (280)
STAB22H3 (222)
Ken Butler (34)
Lecture 14

# STAB22-LEC14-(14,15).docx

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Department
Statistics
Course
STAB22H3
Professor
Ken Butler
Semester
Fall

Description
STAB22LEC14CHAPTER 14 FROM RANDOMNESS TO PROBABILITY175 PROBABILITY RULES AND AN EXAMPLE USING ADDITION RULEThe probability1 must be bween 0 and 1 inclusive2 of an entire sample space is 1003 ADDITION RULE If events A and B have no common outcomes ie they are disjointthen probability of either A or B is PAPBif the proposed events have nth in common then can work out chance of getting either one by adding up their probabilites ex Rolling a fair sixsided die6 diff things that can happen S123456this is a mathematical setit is telling us that in event S there are 6 possible outcomes you roll and you get a 12345 or 6the numbers in the brackets are outcomesGiven the dice is fair rolling any of the six sides is equally likely probability is 16 for any of the six sidesNow check if outcomes in sample space S add up to 116161616161666100ex Let event A be 5 spots or more A 56 B be 2 spots or fewer B21 Question What is probability that either A or B happensAnswernote that there are 4 out of the 6 possible dice rolls that can satisfy this probabilityPA or B PAPB16161616 46either can get 1 2 5 or 6 to win 176 ANOTHER EXAMPLE USING ADDITION RULEex2 Let A be event 5 spots or moreA56 Let C be event even number of spotsC246 Question can we use ADDITION RULE to find PA or C what happens if we do what is the correct answerAnswertrying ADDITION RULEPA or C263656
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