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1. Genes F and Q are linked. In an individualof genotype Fq/fQ, what possible gamete genotypes can beproduced, assuming that meiosis occurs normally?

A. F, f, Q, q

B. Ff, Ff, Qq, Qq

C. FQ, fq, Fq, fQ

D. Ff, Qq, FQ, fq, Fq, fQ

E. Fq, fQ

2. In question #1, what possible gamete genotypes can beproduced if recombination never occurs?

A. F, f, Q, q

B. Ff, Ff, Qq, Qq

C. FQ, fq, Fq, fQ

D. Ff, Qq, FQ, fq, Fq, fQ

E. Fq, fQ

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Keith LeannonLv2
29 Sep 2019
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In the ZZ-ZW sex-determination system, if an AaBb female was crossed to an individual of genotype Aa Bb, what is the probability of a female offspring with the two dominant traits given by alleles A and B? Assume A and B are dominant alleles.

1/8
1/16
9/16
9/32

1.) This summer, there was a surge in the number of albino children killed for their body parts in the African country of Malawi (yes, it's bizarre but sadly true: http://goo.gl/8o0imm and http://goo.gl/DK0r8M). Albinism in humans is inherited as a simple recessive trait. Assuming that two non-albino (normal) parents have five children, four of which are normal and one of which is albino, which of the following statements is true? Select all that apply (you must select all correct answers to get credit). Assume that 'A' indicates the non-albino allele and 'a' indicates the albino allele.

Multiple answers:You can select more than one option

A)The 4 normal children are heterozygous Aa

B)At least one of the normal siblings must be homozygous AA

C)The frequency of albino children is as expected for Mendelian inheritance

D)One of the parents cannot be Aa

E)One third of the normal children expected to be AA while the others Aa

2.)

Albinism in humans is inherited as a simple recessive trait. Assuming that a normal male and an albino female have 6 children, all normal, which of the following statements is true? Select all that apply (you must select all correct answers to get credit).

Multiple answers:You can select more than one option

A)The father could be heterzygous for the trait

B)The probability that all the children are heterozygous for the trait is (1/2)^5 = 1/32

C)The father cannot be Aa

D)The children should all be heterozygous for the trait

E)One would expect about 2/3 of the normal children to be Aa

F)The father must be AA

3.)

Given an albino male mating with a normal female to produce 3 normal children and 3 albino children, which of the following of Mendel's postulates are not being demonstrated by this particular scenario? Select all that apply (to get credit, all your choices must be correct).

Multiple answers:You can select more than one option

A)Postulate of segregation

B)Postulate of dominance

C)Postulate of independent assortment

D)Postulate of unit factors

4.)

Consider the cross: Ee ff Gg HH x Ee Ff gg HH (assume these are designations for genes that are inherited in a Mendelian fashion). What is the probability that a single offspring from this cross would be genotypically: ee Ff Gg HH or Ee ff gg HH?

A)1/16

B)1/32

C)9/64

D)1/6

E)3/16

F)27/64

G)1/64

H)3/64

I)1/8

J)3/8

1) Enter a numerical decimal fraction.Last week you were wondering what Jessica and Tom's babies might look like with respect to their eyebrows and earlobes (both Tom and Jessica have thick eyebrows, controlled by gene E, with thick eyebrows dominant to thin eyebrows, and both of them have free earlobes, controlled by gene F, with free earlobes dominant to attached earlobes). You know that Tom's mom has attached earlobes. Additionally, Tom's mom has thin eyebrows, and so does Jessica's dad. No one in Jessica's pedigree going back to her great grandparents are known to have had attached earlobes, so you assume that she must be homozygous for this trait. If your inferences based on their known pedigrees are correct, what is the probability that Jessica's and Tom's first baby will have free earlobes and thin eyebrows?

2)

Years pass, and Jessica and Tom just had a kid, and they send you a picture of the three of them. You are surprised to see that the baby has thin eyebrows and attached earlobes.

What does this tell you?

Select all the answers that apply:

Select one or more:

a. At least some of Jessica's direct ancestors must be carriers for the recessive allele of gene E, including at least one of her parents.

b. Jessica's dad must be 'true-breeding' for both gene E and gene F.

c. Jessica's mom must be a carrier for gene E.

d. Jessica's genotype must be Ee Ff.

e. Given what you know now about Jessica and Tom's genotypes after seeing their first baby, you realize that prior to inception, the chances of their child showing the thin eyebrow, attached earlobe phenotype was only 1/16.

f. Tom's genotype must be Ee ff.

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