Textbook ExpertVerified Tutor
15 Nov 2021
Given information
We have given that the initial speed of projectile is 36.6 m/s and fired at an angle of 42.2° above the horizontal on a long flat firing range.
Step-by-step explanation
Step 1.
As we know that at maximum height final velocity is zero.
Now we wil calculate the maximum height projectile reached with the help of third equation of motion.
The third equation of motion is :
Here v is final velocity of projectile, u is initial velocity of projectile, g is gravitational acceleration and h is maximum height reached by projectile.
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5a
- Problem 5b
- Problem 5c
- Problem 6a
- Problem 6b
- Problem 7a
- Problem 7b
- Problem 7c
- Problem 8a
- Problem 8c
- Problem 9a
- Problem 9b
- Problem 10a
- Problem 10b
- Problem 11
- Problem 12a
- Problem 12b
- Problem 13a
- Problem 13b
- Problem 13c
- Problem 14
- Problem 15
- Problem 16a
- Problem 16b
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26a
- Problem 26b
- Problem 27a
- Problem 27b
- Problem 27c
- Problem 27d
- Problem 28a
- Problem 28b
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33a
- Problem 33b
- Problem 33c
- Problem 34
- Problem 35
- Problem 36
- Problem 37a
- Problem 37b
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43a
- Problem 43b
- Problem 44a
- Problem 44b
- Problem 45
- Problem 46a
- Problem 46b
- Problem 47a
- Problem 47b
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52c