Given information
Time required for a projectile to reach its heighest point is equal to the time for it to return to its original height .
Step-by-step explanation
Lt the highest point is 
and the time required to reach the maximum height is 
. Let the projectile was projected from the ground. So initial height from the ground will be zero.
Let the projectile makes an angle 
with the horizontal .And let the initial velocity of the projectile is 
.
Thus the vertical component of velocity will be 
.
At the highest point the vertical component of velocity will be zero and there is only horizontal component of velocity.
So considering vertical motion and applying equation of motion 
, Here 
and 
are final and initial velocities respectively in the vertical direction .
is acceleration due to gravity and 
is time.
Substituting the value 
Or 
Unlock all Textbook Solutions
Physics: Principles with Applications
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5a
- Problem 5b
- Problem 5c
- Problem 6a
- Problem 6b
- Problem 7a
- Problem 7b
- Problem 7c
- Problem 8a
- Problem 8c
- Problem 9a
- Problem 9b
- Problem 10a
- Problem 10b
- Problem 11
- Problem 12a
- Problem 12b
- Problem 13a
- Problem 13b
- Problem 13c
- Problem 14
- Problem 15
- Problem 16a
- Problem 16b
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26a
- Problem 26b
- Problem 27a
- Problem 27b
- Problem 27c
- Problem 27d
- Problem 28a
- Problem 28b
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33a
- Problem 33b
- Problem 33c
- Problem 34
- Problem 35
- Problem 36
- Problem 37a
- Problem 37b
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43a
- Problem 43b
- Problem 44a
- Problem 44b
- Problem 45
- Problem 46a
- Problem 46b
- Problem 47a
- Problem 47b
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52c