STAB22H3 Lecture 14: STAB22-LEC14-(14,15).docx
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STAB22H3 Full Course Notes
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1) must be b/ween 0 and 1 (inclusive: of an entire sample space is 1. 00. Probability rules, and an example using addition rule. If events a and b have no common outcomes (ie. they are disjoint), then probability of either a or b is: => if the proposed events have nth in common, then can work out chance of getting either one by adding up their probabilites. (ex) 6 diff. things that can happen roll and you get a] 1,2,3,4,5 or 6. Given the dice is fair, rolling any of the six sides is equally likely. Now, check if outcomes in sample space s add up to 1. S = {1,2,3,4,5,6} - it is telling us that in event s, there are 6 possible outcomes: [you. The numbers in the brackets are outcomes. Probability is 1/6 for any of the six sides.
