MATH 151 Midterm: MATH 151 TAMU Y2009 2009c Exam 1a Solutions

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31 Jan 2019
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F (x) = 1, lim x 1 only to check continuity for x = 1 and x = 2. lim lim x 1 x 1+ f (x) = 2. f (x) does not exist, hence f (x) is not. Thus continuous at x = 1. lim lim x 2+ x 2 is continuous at x = 2. The only place of discontu- nity is x = 1. f (x) = 1, f (2) = 1, thus f (x) f (x) = 1: b: lim x 3+ x 1 x2(x + 3) cal asymptote and. = since x = 3 is a verti- x 1. < 0 for x > 3. x2(x + 3: d: first, note f (x) = x3 x2 + 3x 1 is continuous, so we will apply the intermediate value theorem. 3x denominstor by x: x x x2 + 3x.

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