MGMT 1000 Chapter Notes - Chapter 18: Memory Buffer Register, Opcode, Maximum Capacity

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MGMT 1000 Chapter 18 Notes Summary
Introduction
The original IBM PC came supplied with 64 KB of memory, with a maximum capacity of
640 KB.
In fact, Bill Gates, of Microsoft, was quoted at the time as saying that he could see no
need for more than 640 KB of memory, ever!
The size of the data word to be retrieved or stored in a single operation is determined
by the size of the memory data register and by the width of the connection between
memory and the CPU.
In most modern computers, data and instructions found in memory are addressed in
multiples of 8-bit bytes.
This establishes the minimum instruction size as 8 bits.
Most instructions cannot fit practically into 8 bits. If one were to allow 3 bits for the op
code (eight instruction types), only 5 bits remain for addressing.
Five bits allows 25 = 32 different addresses, which is clearly insufficient address space.
As a result, longer instructions of 16, 24, 32, or even more bits will be stored in
successive memory locations.
In the interest of speed, it is generally desirable to retrieve an entire instruction with a
single fetch, if possible.
Additionally, data to be used in arithmetic calculations frequently requires the precision
of several bytes.
Therefore, most modern computer memories are designed to allow the retrieval or
storage of at least 4 and, more commonly, 8 or even 16, successive bytes in a single
operation.
Thus, the memory data register is usually designed to retrieve the data or instruction(s)
from a sequence of several successive addresses all at once.
The MDR will be several bytes wide section(s) from a sequence of several successive
addresses all at once, and the MDR will be several bytes wide.
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