Homework Help for Chemistry

181,902 results

Chemistry is the science that deals with the structure, properties and transformations of the bodies based on their composition.

For unlimited access to Homework Help, a Homework+ subscription is required.

Avatar image
kyojuro answered this question
in Chemistry·
3 Jul 2022

Show transcribed data

3- A compound insoluble in water, sodium hydroxide, and hydrochloric acid but soluble in concentrated sulfuric acid and containing nitrogen melted at 68°C. When treated with tin and hydrochloric acid, it yielded a substance that reacted with benzenesulfonyl chloride to give an alkali- soluble derivative. When the original compound was treated with zinc and hot sodium hydroxide solution, it was converted to a new substance melting at 130°C.

The product of the reaction with tin and hydrochloric acid was neutralized with base and then distilled. This distillate (in ) gave rise to the following IH NMR (60 MHz) spectrum: 5 3.32, 2H, s; 5 6.44, 2H, m; 5 6.6, 1H, m; 5 7.0, 2H, m.

 

4- A brown liquid (1) boiled at 193-195°C. It contained nitrogen but gave negative tests for sulfur and the halogens. It was insoluble in water but soluble in dilute acid. It did not react with acetyl chloride or benzenesulfonyl chloride. Treatment of a hydrochloric acid solution of the unknown compound with sodium nitrite, followed by neutralization, gave a compound (II) that melted at 164°C. Compound II was insoluble in alkalies but dissolved in boiling concentrated sodium hydroxide solution, with the liberation of a gas (III). This gas (III) was absorbed in water, and the aqueous solution was treated with phenyl isothiocyanate to form a compound (IV) with a melting point of 134-135°C. Careful acidification of the alkaline solution, followed by extraction, gave a compound (V) that melted at 125-126°C.

The 'H NMR spectrum of compound V(60 MHz, acetone) showed 1) 6.63, 2H, d; 1) 7.67, 2H, d; 1) 8.7, 1H, bs. The 1) 8.7 Signal was so broad as to be

Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question
Avatar image
kyojuro answered this question

Start filling in the gaps now
Log in